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Plant Growth and Development: questions with answers

Class 11 Biology, Chapter 13 (NCERT). 15 questions by concept, 8 with pictures. Open “Show answer” for the answer and why.

How to teach this chapter · Common misconceptions & worked visual for this chapter

Growth definition, measurement and indeterminate meristems

Question 1

The neutral diagram marks a meristematic region with ? and shows the direction in which it adds growth. Which interpretation is consistent with the marked position and arrows?

?
  1. (a)A lateral vascular cambium drives primary elongation at the shoot tip.
  2. (b)The arrows show only water movement, so meristem position cannot be related to growth direction.
  3. (c)A lateral vascular cambium drives secondary increase in girth.
  4. (d)The marked meristem makes every leaf, flower and fruit retain unlimited division and growth.
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(c) A lateral vascular cambium drives secondary increase in girth.

A lateral cambium adds cells in a radial pattern for secondary growth. Plant growth is open because particular meristems retain division capacity; this does not mean that every differentiated organ grows indefinitely.

Question 2

Which comparison correctly links meristem location, growth outcome and the meaning of open growth in plants?

  1. (a)Apical meristems chiefly increase girth; lateral cambia chiefly lengthen axes; both remain active in selected regions.
  2. (b)Apical meristems chiefly lengthen axes; lateral cambia chiefly increase girth; selected meristems, not every organ, retain growth capacity.
  3. (c)Apical meristems chiefly lengthen axes; lateral cambia chiefly increase girth; every leaf and flower therefore grows indefinitely.
  4. (d)Apical and lateral meristems both act only during embryo formation; mature plants have no open growth.
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(b) Apical meristems chiefly lengthen axes; lateral cambia chiefly increase girth; selected meristems, not every organ, retain growth capacity.

Root and shoot apical meristems chiefly add primary length along an axis, whereas vascular and cork cambia add secondary girth. Open growth refers to persistent division in selected meristems, while many daughter cells differentiate and lose division capacity.

Growth phases, root zones and environmental conditions

Question 3

Initially equal marks were placed near a growing root tip; later, the interval immediately behind the apex increased most. Which conclusion best fits this evidence?

Root-marking observationOriginally equal marks are followed over time from the same fixed base. The marked interval nearest the tip increases most, and the later root is longer. No growth-zone identity is given. QUESTION DIAGRAM Root-marking observation Same marks tracked · no quantitative scale 1 2 3 4 5 6 Initially 1 2 3 4 5 6 Later Numbers track marks; they are not measurements.
  1. (a)The apical meristem itself makes the greatest contribution to length increase because its cells divide actively.
  2. (b)The observation cannot distinguish elongation from maturation because both zones undergo the same cellular changes.
  3. (c)The maturation zone lies at the apex, followed by elongation and then the meristematic zone.
  4. (d)The elongation zone immediately behind the apical meristem makes the greatest contribution to root length increase.
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(d) The elongation zone immediately behind the apical meristem makes the greatest contribution to root length increase.

The greatest increase in spacing identifies the elongation zone immediately behind the apical meristem. The meristem supplies new cells by division; elongation produces greatest extension, and maturation farther away brings wall thickening and specialisation.

Question 4

A learner writes: “Because division occurs at the apex, the apex also shows the greatest length increase.” Which replacement gives a complete correct account?

  1. (a)From the apex outward, meristematic cells divide, elongating cells enlarge most, and maturing cells thicken walls and specialise.
  2. (b)From the apex outward the order is correct, but elongation and maturation still involve the same enlargement and specialisation changes.
  3. (c)From the apex outward the order is correct, and the meristematic zone still contributes the greatest length increase.
  4. (d)From the apex outward, maturation comes first, elongation second and meristematic division last.
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(a) From the apex outward, meristematic cells divide, elongating cells enlarge most, and maturing cells thicken walls and specialise.

From the growing root tip toward the older root, the meristematic region supplies new cells by division, the elongation region increases length mainly through cell enlargement, and the maturation region develops specialised cells. The region with the most active division is therefore not the same as the region with the greatest extension.

Arithmetic, geometric and sigmoid growth patterns

Question 5

The unlabelled diagram uses a continuation arrow when a daughter divides again and a short terminal bar when a daughter matures. Which interpretation of the diagram is correct?

  1. (a)Both daughters keep dividing, so the lineage has multiplicative increase.
  2. (b)One daughter keeps dividing while the other matures; this is geometric growth with multiplicative increase.
  3. (c)One daughter keeps dividing while the other matures; this is arithmetic growth with additive increase.
  4. (d)One daughter keeps dividing while the other matures, yet total increase is multiplicative.
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(c) One daughter keeps dividing while the other matures; this is arithmetic growth with additive increase.

Only one daughter retains division capacity at each arithmetic division; the other differentiates. This division rule links daughter-cell fate with additive or multiplicative growth.

Question 6

The unlabelled graph plots biological size against time. Which interpretation best matches the shape shown?

TimeSize
  1. (a)A shallow rise, steep middle and plateau represent resource-limited sigmoid growth.
  2. (b)The S-like rise represents arithmetic growth at one unchanged rate throughout.
  3. (c)The S-like rise remains exponential indefinitely after its steep middle.
  4. (d)The S-like rise shows growth stopping before any exponential phase occurs.
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(a) A shallow rise, steep middle and plateau represent resource-limited sigmoid growth.

Natural resource limitation changes the trajectory from lag through a steep exponential region to a stationary plateau. Curve shape reflects whether increase remains constant, accelerates under ideal conditions, or slows as resources become limiting.

Absolute and relative growth rates and growth equations

Question 7

A learner writes: ‘For Lt=L0+rtL_t=L_0+rt, the rate equals the final length, so time can be ignored. For W1=W0ertW_1=W_0e^{rt}, calculate erte^{rt} and use that alone as W1W_1.’ Which diagnosis is complete?

  1. (a)Only the arithmetic step is wrong; exponential final size is independent of W0W_0 once erte^{rt} is known.
  2. (b)Only the exponential step is wrong; in arithmetic growth the rate itself is the final length without time.
  3. (c)Both steps are wrong: arithmetic size is L0+rtL_0+rt, and exponential size is W0W_0 multiplied by erte^{rt}.
  4. (d)Both steps are correct because each equation contains the rate symbol rr.
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(c) Both steps are wrong: arithmetic size is L0+rtL_0+rt, and exponential size is W0W_0 multiplied by erte^{rt}.

The first claim confuses a rate with a size and omits both starting value and elapsed time. The second drops the required multiplier W0W_0; the exponential factor must be applied to the initial size.

Differentiation, dedifferentiation and redifferentiation

Question 8

Two descendants of a root apical meristem occupy different positions. One is pushed toward the outer periphery of the root. According to position-dependent open differentiation, which fate is expected for that cell?

Position of a root descendantA descendant is displaced toward the outer periphery of a root; its future cell identity is unknown. QUESTION DIAGRAM Position of a root descendant Schematic · not to scale Descendant Root cap Toward shoot
  1. (a)It must become a root-cap cell solely because it arose from the same meristem.
  2. (b)It must first form interfascicular cambium because all root-apical-meristem descendants dedifferentiate.
  3. (c)Its peripheral position can direct it toward an epidermal fate.
  4. (d)Its position is irrelevant; every descendant of that meristem must acquire one identical fate.
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(c) Its peripheral position can direct it toward an epidermal fate.

Use the stated position, rather than shared meristematic origin alone.

Tip-facing displacement toward the cap can direct root-cap fate; peripheral displacement can direct epidermal fate.

Its peripheral position can direct it toward an epidermal fate. This positional dependence is called open differentiation.

Question 9

A learner says, “Differentiation is simply continued cell division.” Which correction is complete?

  1. (a)Differentiation produces specialised mature structure, often after division capacity is lost, and those changes suit the cell's function.
  2. (b)Differentiation is continued cell division without gaining any specialised mature structure.
  3. (c)Differentiation occurs only when a mature cell first regains the capacity to divide and forms a new meristem.
  4. (d)Differentiation changes mature structure, but those changes need not fit the function performed by the cell.
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(a) Differentiation produces specialised mature structure, often after division capacity is lost, and those changes suit the cell's function.

Differentiation is maturation into a specialised state, commonly after the cell loses division capacity. In tracheary elements, loss of protoplasm and lignocellulosic wall development are directly suited to water conduction under tension.

Development, plasticity and intrinsic–extrinsic control

Question 10

The paired leaves in the figure come from one larkspur plant at juvenile and adult phases. Which interpretation is correct?

larkspurjuvenileadult
  1. (a)The difference is phase-dependent heterophylly. PGRs are intrinsic controls.
  2. (b)The difference is phase-dependent heterophylly. PGRs are extrinsic environmental factors.
  3. (c)The leaf forms prove that neither life phase nor environment affects development, and PGRs are not developmental controls.
  4. (d)All heterophylly has one common cause, so this comparison cannot distinguish life phase from environment. PGRs are intrinsic controls.
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(a) The difference is phase-dependent heterophylly. PGRs are intrinsic controls.

The difference is phase-dependent heterophylly. This illustrates plasticity: a plant can follow different developmental pathways in response to its life phase or its environment. PGRs are intrinsic intercellular chemical controls, even though extrinsic conditions may act through them.

Question 11

Which classification and interpretation of developmental controls is correct?

  1. (a)Genes and PGRs are intrinsic; light and temperature are extrinsic; plasticity may respond to life phase or environment.
  2. (b)Genes are intrinsic, but PGRs, light and temperature are all extrinsic because they can influence development.
  3. (c)Light and temperature are intrinsic, whereas genes and PGRs are extrinsic controls.
  4. (d)Genes and PGRs are intrinsic, but all heterophylly must arise from life phase alone.
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(a) Genes and PGRs are intrinsic; light and temperature are extrinsic; plasticity may respond to life phase or environment.

Genetic factors and intercellular chemicals such as PGRs are intrinsic controls. Light, temperature, water, oxygen, nutrition and gravity are extrinsic controls; an extrinsic factor may act through a PGR without turning the PGR itself into an external factor. Plasticity may reflect life phase or environment.

PGR identity, functional groups and discovery evidence

Question 12

The figure compares intact, tip-removed and tip-covered coleoptiles under unilateral light. Which combined conclusion is supported?

Unilateral light from leftIntactTip removedTip covered
  1. (a)The tip supplies a phototropic influence that can travel down; kinetin is non-natural in plants, and distinct observations led to distinct PGR discoveries.
  2. (b)The coleoptile base is the source because bending occurs below the tip; kinetin is non-natural in plants.
  3. (c)The tip supplies the influence, but the coleoptile, bakanae and ripening-volatile observations are evidence that can replace each other.
  4. (d)The tip supplies the influence, but kinetin is a naturally occurring plant cytokinin and zeatin is not.
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(a) The tip supplies a phototropic influence that can travel down; kinetin is non-natural in plants, and distinct observations led to distinct PGR discoveries.

The coleoptile tip senses unilateral light and supplies a transmissible influence that causes bending below; the bending region is not the source. The Darwins located this influence, while Went later isolated auxin. Kinetin was obtained from autoclaved herring-sperm DNA and is not naturally present in plants; zeatin is a natural cytokinin.

Question 13

Which comparison keeps chemical identity separate from broad functional grouping?

  1. (a)Auxins, gibberellins and cytokinins are chiefly promoters because all PGRs belong to one chemical class.
  2. (b)Auxins, gibberellins and cytokinins are chiefly promoters, but they are chemically diverse; ethylene is largely inhibitory yet can fit either broad group.
  3. (c)Chemical identity alone determines whether a PGR must promote or inhibit every plant response.
  4. (d)Every PGR is permanently a promoter or permanently an inhibitor, so ethylene cannot fit either broad group.
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(b) Auxins, gibberellins and cytokinins are chiefly promoters, but they are chemically diverse; ethylene is largely inhibitory yet can fit either broad group.

IAA is an indole compound, kinetin an adenine derivative, ABA a carotenoid derivative, GA3 a terpene and ethylene a gas. Auxins, gibberellins and cytokinins are chiefly promoters, ABA is chiefly inhibitory, and ethylene can fit either group but is largely inhibitory; these are not rigid chemical or functional equivalences.

PGR physiological effects, applications and interactions

Question 14

The figure compares a plant with an intact apex and one with the apex removed. What are the intact apex's effect on lateral buds, auxin's effect on fruit drop by age, and gibberellin's effect on stems?

Intact apexApex removed
  1. (a)Buds promoted; early drop prevented, older fruit drop promoted; stems lengthened
  2. (b)Buds suppressed; early drop prevented, older fruit drop promoted; stems shortened
  3. (c)Buds suppressed; early and older fruit drop prevented; stems lengthened
  4. (d)Buds suppressed; early drop prevented, older fruit drop promoted; stems lengthened
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(d) Buds suppressed; early drop prevented, older fruit drop promoted; stems lengthened

Removing the apical bud releases lateral buds because the growing apex normally suppresses their growth. Auxin prevents early fruit drop but promotes abscission of an older mature fruit. Gibberellins promote stem elongation and bolting.

Question 15

Which comparison correctly distinguishes response direction while allowing overlapping PGR control?

  1. (a)Ethylene can break dormancy and ABA induces dormancy, but each broad response is controlled by exactly one PGR.
  2. (b)Ethylene can break dormancy, ABA promotes germination and opens stomata, and responses may involve several PGRs.
  3. (c)Ethylene can break dormancy, ABA induces dormancy and closes stomata, and a broad response may involve more than one PGR.
  4. (d)Ethylene only maintains dormancy, ABA induces dormancy and closes stomata, and responses may involve several PGRs.
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(c) Ethylene can break dormancy, ABA induces dormancy and closes stomata, and a broad response may involve more than one PGR.

Ethylene breaks seed and bud dormancy, whereas ABA induces dormancy and inhibits germination. ABA promotes stomatal closure under stress. PGR effects can overlap or interact: for example, more than one regulator can influence dormancy, senescence, abscission or apical dominance.

Common misconception in Plant Growth and Development

Open full misconception guide →

Does growth mean only getting bigger?

Wrong

A bigger plant organ always has more cells.

Why it feels right. I use size as a count of cells.

Right

Growth can involve cell division and cell enlargement.

Worked example

From tip toward base
Root cap→Cell division zone→Cells lengthen farther back
Different root zones contribute to growth in different ways.
  1. Cells in one zone near a root tip divide.
  2. Farther from the tip, cells can lengthen as they pass through the zone of elongation.