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Classification of Elements and Periodicity in Properties: questions with answers

Class 11 Chemistry, Chapter 3 (NCERT). 15 questions by concept. Open “Show answer” for the answer and why.

How to teach this chapter · Common misconceptions & worked visual for this chapter

Mendeleev's predictions and the modern periodic law

Question 1

Why did Mendeleev place iodine after tellurium despite their atomic weights?

  1. (a)He always placed heavier elements first
  2. (b)That placement preserved similarity with the halogens
  3. (c)Iodine had no measured mass
  4. (d)Tellurium was an alkali metal
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(b) That placement preserved similarity with the halogens

Mendeleev prioritized recurring chemical properties over strict mass order.

Question 2

What did the gaps under aluminium and silicon represent?

  1. (a)Predicted undiscovered elements
  2. (b)Spaces reserved for isotopes
  3. (c)Errors in printing the table
  4. (d)Elements known to be impossible
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(a) Predicted undiscovered elements

Eka-aluminium and eka-silicon were predictions later matched by Ga and Ge.

Need for classification and historical periodic schemes

Question 3

Mendeleev's periodic law related properties primarily to what quantity?

  1. (a)Atomic weight
  2. (b)Nuclear spin
  3. (c)Neutron number
  4. (d)Atomic number
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(a) Atomic weight

The historical law used atomic weight; atomic number became the modern basis.

Question 4

What evidence did Mendeleev use besides atomic weight?

  1. (a)Only alphabetical order
  2. (b)Only colour of the free element
  3. (c)Only date of discovery
  4. (d)Similar formulas and chemical properties of compounds
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(d) Similar formulas and chemical properties of compounds

Chemical similarity determined vertical grouping and sometimes overrode strict mass order.

Electronic configuration, periodic position, and blocks

Question 5

An element ends in 3s²3p⁴. Where is it located?

  1. (a)Period 4, group 3, d block
  2. (b)Period 3, group 16, p block
  3. (c)Period 3, group 4, s block
  4. (d)Period 2, group 16, p block
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(b) Period 3, group 16, p block

Highest n is 3, the last subshell is p, and ns²np⁴ corresponds to group 16.

Question 6

How many columns are in the d block?

  1. (a)14
  2. (b)5
  3. (c)10
  4. (d)8
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(c) 10

Five d orbitals accommodate ten electrons.

Periods, groups, and systematic element nomenclature

Question 7

Using un=1, bi=2, nil=0, what is the temporary name for Z=120?

  1. (a)Biniunium
  2. (b)Unbinilium
  3. (c)Ununbium
  4. (d)Unnilbium
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(b) Unbinilium

Concatenate the digit roots un-bi-nil and add ium.

Question 8

What is the systematic symbol corresponding to unbinilium?

  1. (a)Un
  2. (b)Ub
  3. (c)Ubn
  4. (d)Ubi
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(c) Ubn

The symbol uses the initial of each of the three digit roots.

Block characteristics, metallicity, and second-period anomalies

Question 9

Which property is common among many transition elements?

  1. (a)They form only colourless ions
  2. (b)They are all noble gases
  3. (c)They have only s electrons
  4. (d)Variable oxidation states and catalytic behaviour
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(d) Variable oxidation states and catalytic behaviour

Partly filled d subshells support characteristic transition behaviour.

Question 10

Which d-block set is not typical of transition behaviour because of filled d subshells?

  1. (a)Zn, Cd, and Hg
  2. (b)Sc, Ti, and V
  3. (c)Cr, Mn, and Fe
  4. (d)Fe, Co, and Ni
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(a) Zn, Cd, and Hg

Their common ions retain d¹⁰ configurations and lack many typical properties.

Atomic radius, ionic radius, and isoelectronic ordering

Question 11

How is covalent radius estimated for a homonuclear single bond?

  1. (a)The full bond distance
  2. (b)Half the internuclear distance
  3. (c)Twice the bond distance
  4. (d)The distance from nucleus to a sharp cloud edge
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(b) Half the internuclear distance

Electron clouds lack sharp edges, so an operational half-distance is used.

Ionization enthalpy, successive removal, and exceptions

Question 12

Which process defines first ionization enthalpy?

  1. (a)X(g) → X⁺(g) + e⁻
  2. (b)X(s) → X⁺(aq) + e⁻
  3. (c)X(g) + e⁻ → X⁻(g)
  4. (d)X⁺(g) + e⁻ → X(g)
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(a) X(g) → X⁺(g) + e⁻

The comparison uses isolated gaseous ground-state atoms.

Electron gain enthalpy and electronegativity

Question 13

What does a negative electron gain enthalpy mean?

  1. (a)Energy is released when the gaseous atom gains an electron
  2. (b)The electron has negative mass
  3. (c)Energy must be supplied
  4. (d)The atom loses an electron
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(a) Energy is released when the gaseous atom gains an electron

The sign follows the thermodynamic enthalpy change.

Valence, oxidation state, and periodic compound formulas

Question 14

What formula is expected from aluminium and sulphur using Al³⁺ and S²⁻ tendencies?

  1. (a)Al₃S₂
  2. (b)Al₂S₃
  3. (c)AlS
  4. (d)Al₂S
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(b) Al₂S₃

Two Al³⁺ and three S²⁻ give zero net charge.

Periodic reactivity and acidic-basic character of oxides

Question 15

Why does group-1 reactivity increase down the group?

  1. (a)Valence electron count rises from one to seven
  2. (b)Ionization enthalpy increases sharply
  3. (c)Increasing radius and shielding make electron loss easier
  4. (d)Atoms become smaller
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(c) Increasing radius and shielding make electron loss easier

Lower ionization enthalpy favours cation formation.

Common misconception in Classification of Elements and Periodicity in Properties

Open full misconception guide →

Does an atom get bigger as electrons are added across a period?

Wrong

A chlorine atom is larger than a sodium atom because it has more electrons.

Why it feels right. I assume each extra electron adds another layer.

Right

Across Period 3, added valence electrons enter the same main shell as nuclear charge increases.

Worked example

Both drawings represent Period 3 atoms. The smaller outline represents chlorine's smaller atomic radius.
  1. Sodium and chlorine both have their outermost electrons in the third shell.
  2. The greater effective nuclear attraction in chlorine pulls that shell closer, so chlorine has a smaller atomic radius.