Practice questions › Class 11 › Chemistry › Some Basic Concepts of Chemistry Chemistry, matter, states, and classification Question 1 Air has a uniform but variable composition. How is it classified?
(a) Element (b) Heterogeneous mixture (c) Pure compound (d) Homogeneous mixture Show answer (d) Homogeneous mixture
Uniform distribution makes air homogeneous, while variable composition makes it a mixture.
Question 2 O₂ contains only oxygen atoms joined in pairs. How is O₂ classified?
(a) Homogeneous mixture (b) Element (c) Heterogeneous mixture (d) Compound because each particle has two atoms Show answer (b) Element
An element contains one kind of atom even when its particles are diatomic molecules.
Measurement, SI units, uncertainty, and dimensional analysis Question 3 Which unit factor converts 3.0 in to centimetres using 1 in = 2.54 cm?
(a) 2.54 in/1 cm (b) 1 cm/2.54 in (c) 2.54 cm/1 in (d) 1 in/2.54 cm Show answer (c) 2.54 cm/1 in
The inch unit must be in the denominator so it cancels.
Question 4 Using 1 L = 10⁻³ m³, what is 2.0 L in cubic metres?
(a) 2.0 m³ (b) 2.0 × 10⁻⁶ m³ (c) 2.0 × 10⁻³ m³ (d) 2.0 × 10³ m³ Show answer (c) 2.0 × 10⁻³ m³
Multiply 2.0 L by 10⁻³ m³/L; litres cancel.
Laws of chemical combination and Dalton's atomic theory Question 5 Which Dalton postulate directly supports conservation of mass in a chemical reaction?
(a) Atoms change into different elements (b) Each reactant keeps its original mass (c) Atoms are rearranged but are neither created nor destroyed (d) Equal gas volumes have equal masses Show answer (c) Atoms are rearranged but are neither created nor destroyed
Rearrangement without creation or destruction preserves the total number of each type of atom.
Question 6 Which observation was not explained by Dalton's original atomic theory?
(a) Multiple proportions by mass (b) Simple whole-number ratios of reacting gas volumes (c) Fixed composition of a compound (d) Conservation of total mass Show answer (b) Simple whole-number ratios of reacting gas volumes
Dalton's postulates explained the mass laws but not gaseous-volume relationships.
Atomic, average atomic, molecular, and formula mass Question 7 An element has isotopes of mass 35 u (75%) and 37 u (25%). What is its average atomic mass?
(a) 35.5 u (b) 35.0 u (c) 36.0 u (d) 72.0 u Show answer (a) 35.5 u
Use the abundance-weighted sum: 35(0.75) + 37(0.25) = 35.5 u.
Question 8 An element has isotopes of mass 10 u and 11 u, and its average atomic mass is 10.2 u. Which isotope is more abundant?
(a) Abundance cannot affect average atomic mass (b) The 10 u isotope (c) Both isotopes are equally abundant (d) The 11 u isotope Show answer (b) The 10 u isotope
The weighted average lies much nearer 10 u, so the 10 u isotope is more abundant.
Mass percent, mole fraction, molarity, molality, and dilution Question 9 A solution contains 2.0 g solute and 18.0 g water. What is the solute mass percent?
(a) 11.1% (b) 90% (c) 0.10% (d) 10% Show answer (d) 10%
Mass percent = 2.0/(2.0 + 18.0) × 100 = 10%.
Question 10 A solution contains 2 mol A and 3 mol B. What is the mole fraction of A?
(a) 2.00 (b) 0.67 (c) 0.60 (d) 0.40 Show answer (d) 0.40
xA = nA ÷ (nA + nB) = 2 ÷ 5 = 0.40.
Mole, Avogadro constant, entities, and molar mass Question 11 How many moles are in 36 g H₂O if its molar mass is 18 g mol⁻¹?
(a) 2.0 mol (b) 18 mol (c) 0.50 mol (d) 648 mol Show answer (a) 2.0 mol
n = m ÷ M = 36 ÷ 18 = 2.0 mol.
Question 12 What mass is 0.50 mol CO₂ if its molar mass is 44 g mol⁻¹?
(a) 0.011 g (b) 44 u (c) 22 g (d) 88 g Show answer (c) 22 g
m = nM = 0.50 × 44 = 22 g.
Mass composition, empirical formula, and molecular formula Question 13 Using H = 1 and O = 16, what is the mass percent of hydrogen in H₂O?
(a) 11.1% (b) 88.9% (c) 12.5% (d) 5.56% Show answer (a) 11.1%
Hydrogen contributes 2 of the 18 mass units: (2 ÷ 18) × 100 = 11.1%.
Balanced equations and stoichiometric calculation Question 14 What coefficient of O₂ balances P₄(s) + O₂(g) → P₄O₁₀(s)?
(a) 10 (b) 4 (c) 1 (d) 5 Show answer (d) 5
Five O₂ molecules supply the ten oxygen atoms in P₄O₁₀.
Limiting reagent, excess reagent, and product yield Question 15 For 2A + B₂ → 2AB, a mixture contains 3 mol A and 2 mol B₂. Which reactant is limiting?
(a) A (b) Neither; coefficients cannot compare moles (c) B₂ because 2 is less than 3 (d) Both reactants are fully consumed Show answer (a) A
Two moles B₂ would require 4 mol A, but only 3 mol A is available.
Do equal masses contain equal numbers of molecules? Wrong
18 g of water and 18 g of CO₂ contain the same number of molecules.
Why it feels right. The samples have the same mass on a scale.
Right
The number of molecules depends on the amount in moles, which is mass divided by molar mass.
Worked example
H₂O 6.02 × 10²³
CO₂ 2.46 × 10²³
Both samples weigh 18 g. The water sample has about 2.4 times as many molecules. 18 g of water is about 1 mol, or about 6.02 × 10²³ molecules. 18 g of CO₂ is about 18 ÷ 44 = 0.41 mol, or about 2.46 × 10²³ molecules. Next chapter Structure of Atom