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Class 7 Maths · Chapter 11 · NCERT (gegp203)

Finding Common Ground: common misconceptions

See the tempting mistake students make in Finding Common Ground, why it feels right at first glance, and a worked visual example that shows the right idea.

The tempting mistake & worked visual

When do you need a common factor?

Wrong

The greatest equal packet size for 12 blue beads and 18 red beads is 36.

Why it feels right. I remember finding a common number and use the least common multiple.

Right

To split both colours into equal-sized packs with no leftovers, the pack size must divide both totals.

Worked example

12 blue
🔵🔵🔵🔵🔵🔵
🔵🔵🔵🔵🔵🔵
18 red
🔴🔴🔴🔴🔴🔴
🔴🔴🔴🔴🔴🔴
🔴🔴🔴🔴🔴🔴
A pack of six uses the blue beads in two packs and the red beads in three.
  1. A 36-bead pack cannot be filled from either colour.
  2. Packs of 6 use all 12 blue beads in two packs and all 18 red beads in three.
  3. No larger pack size divides both.

If your child says… (8 concept checks in this chapter)

As you work through Finding Common Ground, listen for these everyday misunderstandings and use the prompt alongside each one.

1. Highest Common Factor (HCF) See how to teach this step →

If your child says… “The HCF should be 1 because factors are small.”

Ask together
Do the 2 cm squares also fit both edges?
What’s true
Choose the greatest factor shared by the measurements.
2. Prime Factorisation See how to teach this step →

If your child says… “Only the primes are factors.”

Ask together
What do the two 2s multiply to?
What’s true
Multiplying available primes together also makes factors of the original number.
3. Finding the HCF of Numbers Using Prime Factorisation See how to teach this step →

If your child says… “I'll take all three 2s.”

Ask together
Where is the third 2 in 12?
What’s true
A shared factor cannot use more copies than either number contains.
4. Lowest Common Multiple (LCM) See how to teach this step →

If your child says… “6 works because it's the longer strip.”

Ask together
Can whole 4 cm strips make a 6 cm row?
What’s true
A shared multiple must divide exactly by each strip length.
5. Finding the LCM Using Prime Factorisation See how to teach this step →

If your child says… “Leave out 3 because only 2 is shared.”

Ask together
Without a 3, how will 6 divide this product?
What’s true
Leaving out any required prime prevents one number from dividing the result.
6. Patterns, Properties, and a Pretty Procedure! See how to teach this step →

If your child says… “The HCF must be smaller than both numbers.”

Ask together
What prevents 2 from dividing both 2 and 6?
What’s true
A number divides itself, so it can be the HCF.
7. Efficient Procedures for HCF and LCM See how to teach this step →

If your child says… “The side divisor gives the LCM too.”

Ask together
Does the side divisor 3 contain enough factors for 6 or 9?
What’s true
The LCM also needs both final quotients when they share only 1.
8. Property Involving both the HCF and the LCM See how to teach this step →

If your child says… “Add the HCF and LCM to get the product.”

Ask together
What operation joins the outside 2 to the bracket?
What’s true
For two positive whole numbers, multiplication joins the HCF and LCM into their product.

Use this chapter three ways