Question 1
How many terms has the sequence 7, 5, 5, 3, 1, 1?
- (a)7
- (b)4
- (c)6
Show answer
(c) 6
A repeated value occupies two positions and is therefore two terms. Counting distinct values would make it a set, which a sequence is not.
Class 11 Maths, Chapter 8 (NCERT). 15 questions by concept. Open “Show answer” for the answer and why.
How to teach this chapter · Common misconceptions & worked visual for this chapter
How many terms has the sequence 7, 5, 5, 3, 1, 1?
(c) 6
A repeated value occupies two positions and is therefore two terms. Counting distinct values would make it a set, which a sequence is not.
For a G.P. with first term 1, finding a term's position gives . Which equation in n follows?
(b)
Since 4 = 2², the right side becomes . Equating exponents now gives .
The sequence 3, 9, 27, 81, ... is formed by multiplying by 3 each time and never stops. Can a last term be named?
(b) No: whatever term is chosen, the rule produces another after it.
The dots say the rule keeps applying. A term that is printed last is not a last term.
In a geometric progression the 3rd term is 54, and the common ratio has been found to be 3. What is the first term?
(c) 6
The value given belongs to its own position. Substituting the ratio back is what recovers the first term.
A sequence is given by aₙ = n² + 5n + 2. What is a₍5₎?
(a) 52
A formula with n in two places needs the position in both. Leaving one standing changes the rule.
How many terms has the series formed from the sequence 3, 6, 12, 24, 48?
(b) 5
A finite sequence gives a series with exactly as many terms.
Two lists are written on the board:
List A: 5, 15, 45
List B: 45, 15, 5
Do the two lists describe the same sequence?
(b) No: the two lists put different numbers in the first position.
Order is part of what a sequence IS. The subscript records position, so two lists holding the same values in different places are different sequences.
A sequence has a₁ = 3 and aₙ = 3aₙ₋₁ + 3 for n > 1. What is a₍4₎?
(a) 120
A recurrence has to be worked through from the seed. Substituting the position into the right-hand side answers nothing.
A geometric progression has first term 3 and common ratio 2. What is its 5th term?
(b) 48
Raising the product would multiply by the first term at every step instead of once.
A nonzero three-term G.P. has common ratio r = 4. Allowing a to take a different value in each naming, which namings can represent this G.P.?
(b) Both a, ar, ar² and a ÷ r, a, ar
Both namings represent the same ordered triple when a is reassigned. In the second naming, a equals the middle term instead of the first.
How many terms has the sum from k = 3 to 14?
(c) 12
The count is upper minus lower PLUS ONE, the same off-by-one that puts the first position at 1 rather than 0.
A geometric progression has first term 2 and common ratio 2. How many of its terms are needed to reach a total of 62?
(c) 5
The total is the sum, so the sum formula is what gets solved. Looking for a term equal to the total finds nothing, because a sum exceeds every term it is made of.
Is the list 4, 0, 0, 0 a geometric progression?
(b) No: once a term is 0 the next ratio cannot be formed.
The definition requires every term to be non-zero, precisely so that every ratio exists.
A geometric progression has first term 5 and common ratio 2. What is the sum of its first 4 terms?
(c) 75
The SUM carries rⁿ. The n − 1 belongs to the general term, which is one term rather than all of them.
4 numbers are inserted between two given numbers so that the whole list is a geometric progression. How many terms has that progression altogether?
(c) 6
Both ends count. k inserted numbers give k + 2 terms, one more than the number of steps.
Wrong
For 2, 4, 8, the third partial sum is 8.
Why it feels right. I use the third term wherever I see the index 3.
Right
A term is one value. A partial sum adds several values.
Worked example
Here a₃ = 8 and S₃ = 2 + 4 + 8 = 14.