Practice questions › Class 8 › Maths › Tales by Dots and Lines Combined changes and the mean Question 1 Two new values shown are each 2 below the original mean, 9. What third value must be added to keep the mean unchanged?
Original17 values:2.5,5,6.5,7,7.5,four8s,9,10,10.5,11,two12s,13,15; original mean9. Two known new values are below9, by 2 and 2 respectively. The third new value is not plotted. Original collection: mean 9 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Known addition 1 2 Known addition 2 2 Third added value: ? (a) 11 (b) 13 (c) 5 (d) 4 Show answer (b) 13
The two known additions are 7 and 7. Three added values must sum to 27, so the third is 27 - 14 = 13.
Mean and median with frequencies Question 2 What is the mean of the observations in this frequency dot plot?
Frequency dot plot. value0:frequency1, value1:frequency5, value2:frequency1, value3:frequency1, value4:frequency1, value5:frequency1 Each dot is one observation 0 1 2 3 4 5 6 7 8 9 10 (a) 2.5 (b) 1.0 (c) 1.9 (d) 0.0 Show answer (c) 1.9
The ten observations total 19, counting all five dots at 1. Their mean is 19 divided by 10, or 1.9.
Mean as the unique balance point Question 3 The marked centre balances the distances. What is the sum of the distances from the dots to its left?
Dots at 2, 4, 9. Centre 5. Separate arrows show distances; repeated dots are separate observations. 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 Centre = 5 (a) 3 (b) 5 (c) 4 (d) 8 Show answer (c) 4
The distances to 2 and 4 are 3 and 1. Their sum is 4, equal to the distance from 5 to 9.
Mean grids Question 4 Each row and column has mean 10. Which lines fail to have mean 10?
Mean grid. rows 6, 13, 11; 10, 8, 12; 14, 9, 7 6 13 11 10 8 12 14 9 7 (a) no lines (b) only the middle column (c) only the middle row (d) both diagonals Show answer (d) both diagonals
The diagonals total 21 and 33, giving means 7 and 11. Each row and column totals 30.
Uniform scaling of the mean Question 5 Every original value is multiplied by 2. What is the new mean, rounded to the nearest hundredth?
Original values3,4,5,6,7,7,8,8,8,10,13 and their scaled values on equal0 to65 axes. Every original observation remains represented. 0 5 10 15 20 25 30 35 40 45 50 55 60 65 Original values 0 5 10 15 20 25 30 35 40 45 50 55 60 65 Every value multiplied by 2 3, 4, 5, 6, 7, 7, 8, 8, 8, 10, 13 Both axes use the same scale (a) 3.59 (b) 14.36 (c) 9.18 (d) 7.18 Show answer (b) 14.36
Doubling every value doubles the total from 79 to 158. The count stays eleven, so the new mean is 158 / 11 158/11 , approximately 14.36.
Means on dot plots Question 6 What is the mean of the four plotted values?
Dots at 10, 10, 11, 17. Each stacked dot is counted separately. 0 2 4 6 8 10 12 14 16 18 19 Each dot is one value (a) 13.5 (b) 10.0 (c) 17.0 (d) 12.0 Show answer (d) 12.0
The four values sum to 48, including both dots at 10. Dividing by 4 gives 12.
Verify and complete a dot plot Question 7 One dot is missing from the plot. The completed collection has mean 9. What is the missing value?
Ten shown values: 4,7,8,8,9,9,9,9,9,11. The missing dot is not drawn. Ten shown values; one dot is missing 0 2 4 6 8 10 12 14 16 (a) 16 (b) 9 (c) 7 (d) 4 Show answer (a) 16
The ten shown values total 83. Eleven values with mean 9 must total 99, so the missing value is 16.
Adding or subtracting the same amount Question 8 Each of the eleven values increases by 3. What is the new mean, rounded to the nearest hundredth?
Top values: 3,4,5,6,7,7,8,8,8,10,13. Bottom adds 3 to each top value. Repeated dots are stacked. Each dot is one value Before 0 2 4 6 8 10 12 14 16 18 20 22 24 Every value +3 0 2 4 6 8 10 12 14 16 18 20 22 24 (a) 7.18 (b) 10.18 (c) 6.91 (d) 7.45 Show answer (b) 10.18
The original sum is 79. Adding 3 to each of eleven values gives total 112, so the new mean is 112 / 11 112/11 , approximately 10.18.
Mean after including or removing one value Question 9 One value, 6, is included in the four-value collection. What is the new mean?
Before: 5, 5, 10, 24. Each stacked dot is counted separately. After include: 5, 5, 10, 24, 6. Each dot is one value Before 4 6 8 10 12 14 16 18 20 22 24 After including 6 4 6 8 10 12 14 16 18 20 22 24 (a) 11.0 (b) 12.0 (c) 6.0 (d) 10.0 Show answer (d) 10.0
The original sum is 44. Including 6 gives a sum of 50 across five values, so the mean is 10.
Choosing a graph representation Question 10 How does the information in the column graph compare with the information in the line graph?
Aligned columns above, lines below; Jan-Dec, Celsius0-40. Approximate Kerala hollow bars/circles: 30.5,31.5,32.5,33,32,30.5,28.8,29.1,29.5,30,31,31. Punjab centre-marked bars/squares: 19,26,29,34,37,38,34.5,35,35.5,33,28,23. Monthly maximum temperature (approximate) Kerala: hollow bars / circles Punjab: centre-marked bars / squares Columns — temperature in Celsius 0 20 40 Lines — temperature in Celsius 0 20 40 Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec (a) monthly observations in columns but yearly observations in lines (b) temperatures in columns but student counts in lines (c) different temperature observations created by joining points (d) the same monthly observations in different forms Show answer (d) the same monthly observations in different forms
Each month has one value for Kerala and one for Punjab in both graphs. Changing the drawing does not change those observations.
Interpreting published graphs Question 11 Which interval shows the larger increase in the USA count of objects launched?
Approximate annual objects launched,2012–2024. Series labelled directly. World and China solid; USA and Russia dashed. Objects launched into space 0 1000 2000 3000 2012 2014 2016 2018 2020 2022 2024 World USA China Russia Approximate source readings; solid / dashed series (a) 2023 to 2024 (b) A decrease in both intervals (c) 2022 to 2023 (d) Equal increases Show answer (c) 2022 to 2023
The USA segment from 2022 to 2023 is much steeper. The higher final point in 2024 does not mean that its preceding increase was larger.
Median positions and changes Question 12 Include 11 in the collection 4, 7, 8, 12, 14. What is the median of the six values?
Dots at 4, 7, 8, 11, 12, 14. Every repeated dot counts separately; no median marker is shown. Each dot is one value 0 2 4 6 8 10 12 14 16 (a) 8 (b) 11 (c) 14 (d) 9.5 Show answer (d) 9.5
The ordered values are 4, 7, 8, 11, 12, 14. The third and fourth values are 8 and 11, whose average is 9.5.
Read line series and changes Question 13 The graph shows sample temperatures for practice. What is the June temperature of the square series?
Practice monthly maximum temperatures. Jan through Dec. Circle series: 30,31,32,33,32,30,29,30,30,31,31,31. Square series: 18,22,26,30,34,36,32,33,34,30,25,21. Circle and square markers distinguish the series. Practice monthly maximum temperatures Circle series Square series °C 0 5 10 15 20 25 30 35 40 Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec (a) 36 (b) 32 (c) 30 (d) 34 Show answer (a) 36
Follow June to the square marker, then read its height: 36°C. The circle marker at June shows 30°C and belongs to the other series.
Reading sun and moon clock graphs Question 14 In this sample, the middle sunset is three five-minute intervals after 18:00. Sunrise is 06:00. What is the middle day’s length in minutes?
Sample adjacent daysA,B,C. Sunrise06:05,06:00,05:55. Sunset17:55,18:00,18:05 plus 3 five-minute steps. Separate morning/evening panels. Sample clock times: three adjacent days Sunrise panel 05:50 05:55 06:00 06:05 06:10 A B (middle) C Sunset panel 17:50 17:55 18:00 18:05 18:10 18:15 18:20 18:25 18:30 18:35 18:40 A B (middle) C Small grid intervals are five minutes Sample times, not a recorded location (a) 723 minutes (b) 705 minutes (c) 735 minutes (d) 750 minutes Show answer (c) 735 minutes
From 06:00 to 18:00 is 720 minutes. Three five-minute intervals add 15 minutes, giving 735 minutes of daylight.
Tables and line-graph values Question 15 Using the exact table entries, what is Mangaluru’s total average number of rainfall days over the twelve months?
Exact monthly rainfall-day table for Mangaluru, Port Blair and Rameswaram. Exact table values: average rainfall days Month Mangaluru Port Blair Rameswaram Jan 0.1 2.4 2.6 Feb 0 1.3 1.3 Mar 0.1 0.9 1.9 Apr 1.8 3.3 3.4 May 6.2 15.5 2.5 Jun 24.1 18.7 0.4 Jul 27.7 17.3 1 Aug 24.5 18.8 1 Sep 14 16.8 1.9 Oct 8.8 14.1 8.1 Nov 3.9 11.3 10.4 Dec 0.9 5.4 7.8 (a) 112.1 (b) 112 (c) 42.3 (d) 125.8 Show answer (a) 112.1
Adding Mangaluru’s twelve exact entries gives 112.1 days. Do not replace them with rounded plotting values when an exact-table total is requested.
Can the average come from just the smallest and largest values? Wrong
The mean of 2, 2, 2 and 10 is 6.
Why it feels right. I averaged the two endpoints on the plot.
Right
Every observation contributes to the mean.
Worked example
2 4 mean 10 Three observations sit at 2 and only one sits at 10. The mean is 4, closer to the cluster. Place three dots at 2 and one at 10. The mean is (2 + 2 + 2 + 10) ÷ 4 = 4. Previous chapter Exploring Some Geometric Themes Next chapter Algebra Play