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Expressions Using Letter-numbers: questions with answers

Class 7 Maths, Chapter 4 (NCERT). 15 questions by concept, 4 with pictures. Open “Show answer” for the answer and why.

How to teach this chapter · Common misconceptions & worked visual for this chapter

A letter standing in for a number

Question 1

Kabir is 5 years older than Ravi. If Ravi's age in years is rr, which expression gives Kabir's age in years?

  1. (a)r+5r + 5
  2. (b)r−5r - 5
  3. (c)5−r5 - r
  4. (d)5r5r
Show answer

(a) r+5r + 5

Kabir is older, so Kabir's age is Ravi's age with 5 added to it, which is r+5r + 5. Subtracting would give the age of someone 5 years YOUNGER than Ravi.

Question 2

Nandini buys dd candles at Rs 12 each and ss kg of sugar at Rs 45 a kg. Nandini pays 12d+45s12d + 45s rupees. What happens to this amount when different quantities are bought?

  1. (a)It depends only on the prices
  2. (b)It changes with the quantities bought
  3. (c)It stays the same
  4. (d)It is always Rs 57
Show answer

(b) It changes with the quantities bought

dd says how many candles are bought and ss says how many kilograms of sugar are bought. Both can be replaced by different numbers on different days. Buying one more candles adds Rs 12 to the amount. Only the two prices, Rs 12 and Rs 45, stay fixed.

The simplest form, and when two expressions are equal

Question 3

At y=5y = 5, the expressions 3y3y and y+10y + 10 both give 15. How do the values of these two expressions compare as yy changes?

  1. (a)Equal at every whole-number value
  2. (b)Different at every value
  3. (c)Equal at every value
  4. (d)Equal at some values, different at others
Show answer

(d) Equal at some values, different at others

Equal expressions must give the same value for ANY value of the letter. Here they agree only at y=5y = 5. At y=6y = 6, 3y3y gives 18 while y+10y + 10 gives 16. So the two expressions are equal at some values and different at others.

Question 4

A rectangle has side lengths aa and dd. For which side lengths do a+d+a+da + d + a + d and 2(a+d)2(a + d) give the same perimeter?

  1. (a)No pair of side lengths
  2. (b)Only equal side lengths
  3. (c)Every pair of side lengths
  4. (d)Only whole-number side lengths
Show answer

(c) Every pair of side lengths

Adding aa twice and dd twice gives 2a+2d2a + 2d. Opening the bracket in 2(a+d)2(a + d) also gives 2a+2d2a + 2d. The two expressions simplify to the same thing, so they give the same perimeter for every pair of side lengths.

Turning a described situation into an expression

Question 5

At Kalyani's stall one plate of Pongal costs Rs 45 and one plate of Vada costs Rs 12. On one day 11 plates of Pongal and 13 plates of Vada were sold. How much was earned, in rupees?

  1. (a)339
  2. (b)651
  3. (c)717
  4. (d)1368
Show answer

(b) 651

11 plates of Pongal at Rs 45 bring in 495, and 13 plates of Vada at Rs 12 bring in 156. Together that is 651. Each price must stay with the count of its own dish; swapping them gives 717.

Question 6

Venkatalakshmi owns a flour mill. When it is switched on the roller takes 15 seconds to start up, and once it is running each kg of grain takes 9 seconds to grind. Which expression gives the number of seconds needed to grind yy kg of grain, starting from switched off?

  1. (a)15×9×y15 \times 9 \times y
  2. (b)(15+9)y(15 + 9)y
  3. (c)15y+915y + 9
  4. (d)15+9y15 + 9y
Show answer

(d) 15+9y15 + 9y

The 15 seconds of starting up happen ONCE, however much there is to grind, so that number is added on its own. Only the 9 seconds are charged for each kg of grain, so they are multiplied by yy, giving 15+9y15 + 9y.

Relationships between positions in a grid

Question 7

Five dates in a calendar form a plus shape: one in the middle, one directly above, one directly below, and one on each side. If the middle date is cc, what is the sum of all five?

Five dates in a calendarA calendar grid with seven columns. Five shaded cells form a plus shape: the middle cell is labelled c, with one shaded cell immediately above, below, left and right. The other dates are not printed. QUESTION DIAGRAM Five dates in a calendar Five neighbouring dates form a plus shape c
  1. (a)c+20c + 20
  2. (b)5c+165c + 16
  3. (c)It cannot be written down without knowing which five dates were chosen
  4. (d)5c5c
Show answer

(d) 5c5c

Written in terms of the middle date, the four arms are c−7c - 7, c−1c - 1, c+1c + 1 and c+7c + 7. Adding all five, the −7-7 cancels the +7+7 and the −1-1 cancels the +1+1, leaving five lots of cc: the sum is 5c5c wherever the shape is placed. That is why the answer can be written at all without knowing which dates were chosen.

Question 8

In the calendar block shown, the marked cell is directly below the cell holding dd. If the dates run left to right along each row, which expression gives the marked date?

d
  1. (a)d+7d + 7
  2. (b)d+1d + 1
  3. (c)d−7d - 7
  4. (d)7d7d
Show answer

(a) d+7d + 7

Moving one place to the RIGHT adds 1, but moving one row DOWN skips a whole week of seven cells, so the date below dd is d+7d + 7. d+1d + 1 is the date to the right of dd, not the one below it.

Finding the value of an expression

Question 9

If m=−6m = -6, what is the value of 3(m+1)3(m + 1)?

  1. (a)-5
  2. (b)19
  3. (c)21
  4. (d)-15
Show answer

(d) -15

Put the whole value into the bracket, minus sign and all: −6+1=−5-6 + 1 = -5. Multiplying by 3 gives -15. Leaving the minus sign behind would make the bracket 6 + 1 = 7 and the answer 21, a positive number where the true value is negative.

Question 10

If h=−2h = -2, what is the value of 11−h+4h11 - h + 4h?

  1. (a)1
  2. (b)21
  3. (c)17
  4. (d)5
Show answer

(d) 5

The letter carries its minus sign into both places it appears. −h-h becomes −(−2)-(-2), which ADDS 2, while 4h4h becomes 4 x (−2)(-2), which SUBTRACTS 8. So the value is 11 + 2 - 8 = 5. Treating the subtraction as an ordinary one gives 1; ignoring the minus sign altogether gives 17.

Like terms and unlike terms

Question 11

Simplify 9h+7−h9h + 7 - h.

  1. (a)1515
  2. (b)9h+79h + 7
  3. (c)8h+78h + 7
  4. (d)15h15h
Show answer

(c) 8h+78h + 7

9h9h and hh are like terms, and the lone hh counts as one of them, so they leave 8 of them. The 7 carries no letter and cannot join them, so the simplest form is 8h+78h + 7.

Opening brackets in an algebraic expression

Question 12

Simplify 7−(2−6v)7 - (2 - 6v).

  1. (a)9−6v9 - 6v
  2. (b)6v−56v - 5
  3. (c)5−6v5 - 6v
  4. (d)5+6v5 + 6v
Show answer

(d) 5+6v5 + 6v

The minus sign subtracts the WHOLE bracket, so every sign inside is reversed as it comes out: 7−2+6v7 - 2 + 6v, which is 5+6v5 + 6v. The 6v6v was being taken away inside the bracket, and taking away a subtraction adds it back.

Writing an expression for a pattern

Question 13

The picture shows a matchstick pattern. Step 1 is one triangle, and each step after it adds one more triangle sharing a side with the last. Which expression gives the number of matchsticks at Step nn?

Step 1Step 2Step 3
  1. (a)3n3n
  2. (b)2n+12n + 1
  3. (c)2n2n
  4. (d)n+2n + 2
Show answer

(b) 2n+12n + 1

Step 1 uses 3 matchsticks, and every step after it adds 2 more, so Step nn uses 3+2(n−1)3 + 2(n - 1), which simplifies to 2n+12n + 1. 3n3n is right at Step 1 but wrong ever after, because the pattern grows by 2 each time and not by 3. 2n2n grows correctly but is one short throughout, since Step 1 needs 3 and not 2.

Question 14

A row of pentagons is built from matchsticks. The first pentagon needs 5 matchsticks, and each further pentagon shares one side with the one before it, so it needs only 4 more. Which expression gives the number of matchsticks needed for mm pentagons?

A shared side in the shape rowTwo representative regular polygons share one side; the requested long row and its matchstick count are not drawn. QUESTION DIAGRAM A shared side in the shape row Two shapes share one full side; the row continues …
  1. (a)5m5m
  2. (b)4m+14m + 1
  3. (c)m+4m + 4
  4. (d)4m4m
Show answer

(b) 4m+14m + 1

The first pentagon costs 5, and each of the other (m−1)(m - 1) costs 4, so the total is 5+4(m−1)5 + 4(m - 1), which simplifies to 4m+14m + 1. Notice the multiplier is the STEP-UP 4, not the first count 5: multiplying by 5 is right only at m=1m = 1.

Writing 4 x n as 4n

Question 15

If y=5y = 5, what is the value of 6y−46y - 4?

  1. (a)61
  2. (b)30
  3. (c)6
  4. (d)26
Show answer

(d) 26

6y−46y - 4 is a sum of the terms 6y6y and −4-4. The first is 6 x 5 = 30, and taking 4 away leaves 26. Reading it as 6 x (5 - 4) would give 6, which is what 6(y−4)6(y - 4) means.

Common misconception in Expressions Using Letter-numbers

Open full misconception guide →

Do like terms multiply when you add them?

Wrong

3x + 2x = 5x²

Why it feels right. I combined the numbers and counted two x symbols.

Right

Adding like terms combines their counts.

Worked example

Start
xxx
xx
Combine
xxxxx
Combining x-tiles counts tiles of the same kind. The tile itself stays x.
  1. Three x tiles plus two x tiles make five x tiles.
  2. At x = 2, the sum is 10, which is 5x.